(1-2y)^2-4y=2

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Solution for (1-2y)^2-4y=2 equation: 



(1-2y)^2-4y=2

We move all terms to the left:

(1-2y)^2-4y-(2)=0

We add all the numbers together, and all the variables

(-2y+1)^2-4y-2=0

We add all the numbers together, and all the variables

-4y+(-2y+1)^2-2=0

We move all terms containing y to the left, all other terms to the right

-4y+(-2y+1)^2=2

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